Two bodies of different masses m1 and m2 (m1>m2) have same kinetic energy . They are stopped by applying some retarding force . Which body will stop first ?

Open in App

Solution

Hello,
Both blocks stop together.
Because KE₁ = KE₂
There is need of same amount of work done by us to stop them.
So W₁= W₂
=> F₁ s₁ = F₂ s₂
Here, F₁ = F₂
Hence, s₁ = s₂
Distance covered by both blocks is same before stop.

Suggest Corrections

Similar questions

If a heavier and a lighter body have the same kinetic energy and they are stopped by applying the same force, which one will stop first?

Q. Two bodies of masses

m_{1}

and

m_{2}

have same kinetic energy. The ratio of their momentum is

Q. Two bodies of different masses

m_{1}

and

m_{2}

have equal momenta. Their kinetic energies

E_{1}

and

E_{2}

are in the ratio:

Q. Same force acts on two bodies of masses

m_{1}

and

m_{2}

(

m_{2}

m_{1}

). After travelling the same distance,

Two bodies of masses $m_{1}$ and $m_{2}$ have equal kinetic energies. If $p_{1}$ and $p_{2}$ are their respective momentum, then ratio $p_{1} : p_{2}$ is equal to

Join BYJU'S Learning Program

Two bodies of different masses m1 and m2 (m1>m2) have same kinetic energy . They are stopped by applying some retarding force . Which body will stop first ?

Hello,Both blocks stop together.Because KE1 = KE2There is need of same amount of work done by us to stop them.So W1 = W2=> F1 s1 = F2 s2Here, F1 = F2Hence, s1 = s2Distance covered by both blocks is same before stop.

Hello,
Both blocks stop together.
Because KE₁ = KE₂
There is need of same amount of work done by us to stop them.
So W₁= W₂
=> F₁ s₁ = F₂ s₂
Here, F₁ = F₂
Hence, s₁ = s₂
Distance covered by both blocks is same before stop.