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Standard X

Chemistry

Chemical Properties

two molecules...

Question

two molecules of organic compound A on treatment with strong solution of NaOH gives two comounds B and C .Compound B on dehydration with Cu gives A while acidification of C yields carboxlic acid having formula of CH₂O_2.Identify compounds A,B,C,D

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Solution

H-CHO + H-CHO + NaOH $\to$ CH₃OH + HCOONa (Cannizaro reaction)
(A) (B) (C)

CH₃OH $\overset{C u / 300 d e g C}{\to}$ HCHO + H₂
(B) (A)
This is a dehydrogenation reaction and not dehydration as mentioned in the question

HCOONa + H⁺ $\to$ HCOOH + Na⁺
(C) (D)

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two molecules of organic compound A on treatment with strong solution of NaOH gives two comounds B and C .Compound B on dehydration with Cu gives A while acidification of C yields carboxlic acid having formula of CH2O2.Identify compounds A,B,C,D

H-CHO + H-CHO + NaOH → CH3OH + HCOONa (Cannizaro reaction) (A) (B) (C) CH3OH →Cu/300 degC HCHO + H2 (B) (A) This is a dehydrogenation reaction and not dehydration as mentioned in the question HCOONa + H+ → HCOOH + Na+ (C) (D)

two molecules of organic compound A on treatment with strong solution of NaOH gives two comounds B and C .Compound B on dehydration with Cu gives A while acidification of C yields carboxlic acid having formula of CH₂O_2.Identify compounds A,B,C,D

H-CHO + H-CHO + NaOH $\to$ CH₃OH + HCOONa (Cannizaro reaction)
(A) (B) (C)

CH₃OH $\overset{C u / 300 d e g C}{\to}$ HCHO + H₂
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This is a dehydrogenation reaction and not dehydration as mentioned in the question

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(C) (D)