two resistors 4 ohm and 6 ohm are connected in parallel.the combination is connected across a 6V of negligible resistance.calculate the a)the current through the battery
b)the current through each resistor?
Given that:
R1=4ohm,R2=6ohm
For parallel combination,
1/R=1/R1 +1/R2
=1/4 +1/6
R=12/5=2.4 ohm
a)the current through the battery
I=V/R=6/2.4=2.5 A
b) Current through 4 ohm resistor
I=6/4=1.5A
Current through 6 ohm resistor
I=6/6=1A