Two resistors of 5 ohms and 10 ohms are connected in series with a supplied potential difference of 30V. Find the potential difference across (1) 5ohms resistor (2) 10ohms resistors

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Solution

$R_{1} = 5 o h m R_{2} = 10 o h m e q u i v a l e n t r e s i s \tan c e w h e n t h e y a r e c o n n e c t e d i n s e r i e s, R = 65 + 10 = 15 o h m V o l t a g e i n t h e c i r c u i t . V = 30 v I = V / R = 30 / 15 = 2 A . I n s e r i e s c u r r e n t r e m a i n s s a m e . V o l t a g e a c r o s s R_{1} = I R_{1} = 2 \times 5 = 10 v V o l a t g e a c r o s s R_{2} = I R_{2} = 2 \times 10 = 20 v$

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Two resistors of 5 ohms and 10 ohms are connected in series with a supplied potential difference of 30V. Find the potential difference across (1) 5ohms resistor (2) 10ohms resistors

R1 = 5 ohmR2 = 10 ohmequivalent resistance when they are connected in series,R = 65 + 10 = 15 ohmVoltage in the circuit.V = 30 vI = V/R = 30/15 = 2 A.In series current remains same.Voltage across R1 = IR1 = 2×5 =10 vVolatge across R2 = IR2 = 2×10 = 20 v