Two strips of metal are riveted togetherat their ends by four rivets, each of diameter 6.0 mm. What is themaximum tension that can be exerted by the riveted strip if theshearing stress on the rivet is not to exceed 6.9 × 107Pa? Assume that each rivet is to carry onequarter of the load.
Diameter of the metalstrip, d = 6.0 mm = 6.0 × 10–3 m
Maximum shearing stress= 6.9 × 107 Pa
Maximum force = Maximumstress × Area
=6.9 × 107 × π× (r) 2
=6.9 × 107 × π× (3 ×10–3)2
=1949.94 N
Each rivet carries onequarter of the load.
∴ Maximumtension on each rivet = 4 × 1949.94 = 7799.76 N