two wires of equal length, one of copper and other of manganin have the same resistance. which wire is thicker?

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Solution

R_copper=R_manganin
l_copper=l_manganin
Ï_copperl_copper/A_copper=Ï_manganinl_manganin/A_manganin
Ï_copper/A_copper=Ï_manganin/A_manganin
A_manganin/A_copper=Ï_manganin/Ï_copper
from this we find that the area that wire is more which has high resistivity.
Resistivity of copper (Ï_copper) is nearly 1.67 Ã— 10^-8 Î© m
Resistivity of manganin (Ï_manganin) is nearly 4.5 Ã— 10^-8 Î© m
so the answer is Manganin

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