urgrent
the enthalpy change for the reaction of 50 ml of ethylene with 50.0 ml of H2 at 1.5 atm pressure is delta H= -0.31 Kj.what is the delta U?

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Solution

the reaction can be written as follows:
C2H4 + H2 â†’ C2H6
the ratio of reactant is 1:1 and product is also forming in ratio of 1,âˆ´ 50 ml of ethylene on reaction with 50 ml of H2 will produce 50 ml. of ethane. change in volume is 50ml (ethane)-100ml (C2H4 + H2) = 50ml= 0.05L
P Î”V=1.5*0.05= 0.075Latm = 7.5joules
Î”U = Î”H + P Î”V = -0.31KJ + 7.5J = -3025KJ

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urgrentthe enthalpy change for the reaction of 50 ml of ethylene with 50.0 ml of H2 at 1.5 atm pressure is delta H= -0.31 Kj.what is the delta U?

urgrent
the enthalpy change for the reaction of 50 ml of ethylene with 50.0 ml of H2 at 1.5 atm pressure is delta H= -0.31 Kj.what is the delta U?