Using -x - a-x - b- - x2 - -a - b-x - ab- find-i-103 times- 104-ii-5-1 times- 5-2 -iii-103 times- 98 -iv-9-7 times- 9-8

(i) 103 times; 104 =(100 + 3) (100 + 4)=(100)2 + (3 + 4) (100) + (3) (4)=10000 + 700 + 12 = 10712(ii) 5.1 times; 5.2 =(5 + 0.1) (5 + 0.2)=(5)2 + (0.1 + 0. ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard VI

Mathematics

Addition of Whole Numbers on Number Line

Using (x + a)...

Question

Using (x + a)(x + b) = x² + (a + b)x + ab, find
(i) 103 × 104 (ii) 5.1 × 5.2 (iii) 103 × 98 (iv) 9.7 × 9.8

Open in App

Solution

(i) 103 × 104 =(100 + 3) (100 + 4)
=(100)² + (3 + 4) (100) + (3) (4)
=10000 + 700 + 12 = 10712
(ii) 5.1 × 5.2 =(5 + 0.1) (5 + 0.2)
=(5)² + (0.1 + 0.2) (5) + (0.1) (0.2)
=25 + 1.5 + 0.02 = 26.52
(iii) 103 × 98 =(100 + 3) (100 − 2)
=(100)² + [3 + (− 2)] (100) + (3) (− 2)
=10000 + 100 − 6
=10094
(iv) 9.7 × 9.8 =(10 − 0.3) (10 − 0.2)
=(10)² + [(− 0.3) + (− 0.2)] (10) + (−0.3) (− 0.2)
=100 + (− 0.5)10 + 0.06 = 100.06 − 5 = 95.06

Suggest Corrections

Similar questions

Using (x + a) (x + b) = x² + (a + b) x + ab, find

(i) 103 × 104 (ii) 5.1 × 5.2 (iii) 103 × 98 (iv) 9.7 × 9.8

Q. Using

(x + a) (x + b) = x^{2} + (a + b) x + a b,

find

103 \times 104

Q. Using

(x + a) (x + b) = x^{2} + (a + b) x + a b,

find

5.1 * 5.2

Q. Using

(x + a) (x + b) = x^{2} + (a + b) x + a b

, find

5.1 \times 5.2

Question 8(iii)
Using $(x + a) (x + b) = x^{2} + (a + b) x + a b$ , find
$103 \times 98$

Join BYJU'S Learning Program

Using (x + a)(x + b) = x2 + (a + b)x + ab, find(i) 103 × 104 (ii) 5.1 × 5.2 (iii) 103 × 98 (iv) 9.7 × 9.8

Using (x + a)(x + b) = x² + (a + b)x + ab, find
(i) 103 × 104 (ii) 5.1 × 5.2 (iii) 103 × 98 (iv) 9.7 × 9.8