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Question
using prime factorisation find the lcm&hcf of 21,28,36,45
using prime factorisation find the lcm&hcf of 21,28,36,45
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Solution
21 = 3 × 7
28 = 2 × 2 × 7
36 = 2 × 2 × 3 × 3
45 = 3 × 3 × 5
So, H.C.F. = 1
L.C.M. = 2 × 2 × 3 × 3 × 5 × 7 = 1260
21 = 3 × 7
28 = 2 × 2 × 7
36 = 2 × 2 × 3 × 3
45 = 3 × 3 × 5
So, H.C.F. = 1
L.C.M. = 2 × 2 × 3 × 3 × 5 × 7 = 1260
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