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Question

P-V curve of a diatomic gas is shown in the figure. Find the total heat given to the gas in the process AB and BC
295933_02190ef50bd947a0ac41540f7333bfc9.png

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Solution

R.E.F image
thermodynamics
Change in internal energy from
AB
Δu=f2nRΔT=f2(P2V2P1V1)
=32(2P0×2V0P0V0)
Hef=3 =9P0V02
AB
Δw=P0(2V0V0)+12×V0×P0
Δw=32P0V0 Required answer
heat change =ΔQ=Δu×Δw
=92P0V0+32P0V0
=6P0V0
Required answer C

1048441_295933_ans_72db6ba71a8c4019bac9e870511ef5d4.png

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