Question

P-V diagram of an ideal gas is shown in figure. Work done by the gas in the process ABCD is:

• A. $2P_{\circ }{V}_{\circ }$
• B. $3P_{\circ }{V}_{\circ }$
• C. $P_{\circ }{V}_{\circ }$
• D. $4P_{\circ }{V}_{\circ }$

Answer 1

Answer: (B)

$3P_{\circ }{V}_{\circ }$

Work Done in process AB is :

$W_{AB}=P_0(V_0-2V_0)=-P_0{V}_0$

Work done in path BC is zero since volume remains constant.

Work done in path CD is :

$W_{CD}=2P_0({3V}_0-V_0)=4P_0{V}_0$

Net work done in path ABCD is $W=W_{AB}+W_{CD}=3P_0{V}_0$