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Question

PV graph for an ideal gas undergoing a polytropic process given by PVn=k is shown below. Find the value of n.



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Solution

Slope of the given PV curve is dPdV=tan (18037)=tan 143=0.75
Given equation of polytropic process is PVn=k
Differentiating on both sides, we get
P×(nVn1)dV+VndP=0
nPVn1dV=VndP
dPdV=nPV
Substituting the data given in the question, we get
0.75=n×2×1054×105
n=1.5

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