The correct option is B O2 and He
For an adiabatic process, PVγ=constant,
Differentiating, we have
γPVγ−1+dPdVVγ=0 or
dPdV=−γPV
Thus, the slope of P−V curve is proportional to γ. Now, for a diatomic gas, γ(=7/5) is less than that for a monoatomic gas for which γ=5/3. Therefore, the slope of the P−V curve is less for a diatomic gas than for a monoatomic gas. Hence curve 1 corresponds to diatomic gas and curve 2 to monoatomic gas. Thus, the correct choice is (b).