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Question

PV plots for two gases during adiabatic processes are shown in Fig. Plots 1 and 2 should correspond respectively to


A
He and O2
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B
O2 and He
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C
He and Ar
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D
O2 and N2
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Solution

The correct option is B O2 and He
For an adiabatic process, PVγ=constant,
Differentiating, we have
γPVγ1+dPdVVγ=0 or

dPdV=γPV
Thus, the slope of PV curve is proportional to γ. Now, for a diatomic gas, γ(=7/5) is less than that for a monoatomic gas for which γ=5/3. Therefore, the slope of the PV curve is less for a diatomic gas than for a monoatomic gas. Hence curve 1 corresponds to diatomic gas and curve 2 to monoatomic gas. Thus, the correct choice is (b).

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