The correct option is B O2 and He
For an adiabatic process,
PVγ=constant
For monatomic gas, γ=CPCV=1.67
For diatomic gas, γ=1.4
⇒γdiatomic<γmonatomic
Since slope of adiabatic curve, dPdV=−γPV
Thus slope of monoatomic will be more than diatomic gas,
Hence, curve 1 represents graph for diatomic gas and curve 2 represents graph for a monomatomic gas
∴Correct option is (b)