Question

volume of co₂ liberated at STP on burning 24g
of methane in excess of air is
1) 11.2L
2) 22.4L
3) 33.6L
4) 44.8L

Answer 1

CH₄ + 2O₂ → CO₂ + 2H₂O
Molar mass of methane (CH₄) = 16 g mol^-1
16 g of CH₄ gives = 22.4 L of CO₂ at STP
24 g of CH₄ gives = $\frac{22.4\times 24}{16}$
Hence , volume of liberated CO₂ is 33.6 L.