Question

wat is the solution for this In a league football team has 17 wins and 3 losses after having played 2/3 of its matches how many matches can i afford to lose. if the team has to win more then 3/4 of the total matches it will play in league?

Answer 1

Let the total number of matches be x.

The number of matches played =$\frac{2}{3}x$

Also number of matches played = 17 +3 =20

Thus,
$$\begin{gathered} \frac{2}{3}x=20 \\ x=20\times \frac{3}{2}=30 \end{gathered}$$

Number of matches left to be played = 30-20 =10

Now, $\frac{3}{4}$ of the total matches =$\frac{3}{4}\times 30=22.5$


The team must win more than 3/4 of the total matches, so it must win more than 22.5 matches or say at least 23 matches

Already won= 17
Remaining to win = 23- 17 =6

Of the remaining 10 matches, 6 must be won, so the team can afford to lose 4 matches