Question

$p\wedge q$ is logically equivalent to

• A. $\sim (p\to \sim q)$
• B. $(p\to \sim q)$
• C. $(\sim p\to \sim q)$
• D. $(\sim p\to q)$

Answer 1

The correct option is A $\sim (p\to \sim q)$

$p$	$q$	$p\wedge q$	$\sim (p\to \sim q)$
$T$	$T$	$T$	$T$
$T$	$F$	$T$	$T$
$F$	$F$	$T$	$T$
$F$	$T$	$T$	$T$

$(p\wedge q)⟶$$\sim (p\to \sim q)$ is a tautology.