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Question

[p(q)][(p)q]

A
a tautology
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B
a contradiction
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C
a contingency
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D
logically equivalent to x (x)
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Solution

The correct option is B a contradiction
We know that,
p(q) (pq),
(pq) pq

Hence [p(q)][(p)q] is a contradiction.
Since we know x (x) is always false.

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