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B
A fallacy
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C
Both a tautology and a fallacy
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D
Neither a tautology nor a fallacy
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Solution
The correct option is B A fallacy The AND connective is associative and commutative. Hence, (p∧∼q)∧(∼p∧q)=(p∧∼p)∧(∼q∧q) This statement is always false.