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Question

(pq)(pq) is

A
A tautology
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B
A contradiction
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C
Both a tautology and a contradiction
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D
Neither a tautology nor a contradiction
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Solution

The correct option is B A contradiction
(pq)(pq)=(pp)(qq)
=ff=f
(By using associative laws and commutative laws)
(pq)(pq) is a contradiction.

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