what is d value of 'x' in d following equation :
[(4x + 3) / 4 ] - { x - [(2x-1) / 3] } = x + (1 / 3)

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Solution

$\frac{(4 x + 3)}{4} - [x - \frac{(2 x - 1)}{3}] = x + \frac{1}{3} \Rightarrow \frac{4 x + 3}{4} - [\frac{3 x - (2 x - 1)}{3}] = \frac{3 x + 1}{3} \Rightarrow \frac{4 x + 3}{4} - [\frac{3 x - 2 x + 1}{3}] = \frac{3 x + 1}{3} \Rightarrow \frac{4 x + 3}{4} - \frac{(x + 1)}{3} = \frac{3 x + 1}{3} \Rightarrow \frac{4 x + 3}{4} = \frac{3 x + 1}{3} + \frac{x + 1}{3} \Rightarrow \frac{4 x + 3}{4} = \frac{3 x + 1 + x + 1}{3} \Rightarrow \frac{4 x + 3}{4} = \frac{4 x + 2}{3} \Rightarrow 3 \times (4 x + 3) = 4 \times (4 x + 2) \Rightarrow 12 x + 9 = 16 x + 8 \Rightarrow 12 x - 16 x = 8 - 9 \Rightarrow - 4 x = - 1 \Rightarrow x = \frac{1}{4}$

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Which of the following is not a quadratic equation?
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(b) $2 x - x^{2} = x^{2} + 5$
(c) ${(\sqrt{2} x + \sqrt{3})}^{2} = 3 x^{2} - 5 x$
(d) $(x^{2} + 2 x)^{2} = x^{4} + 3 + 4 x^{3}$

Q. The value of

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which satisfies the equation

{log}_{\frac{1}{3}} (2 {(\frac{1}{2})}^{x} - 1) = {log}_{\frac{1}{3}} ({(\frac{1}{4})}^{x} - 4)

Q. What is the value of

x

for which the following equation is true?

\frac{1}{x + 3} = \frac{3}{4 x}

$T h e v a l u e o f x i n t h e e q u a t i o n \frac{2 x + 1}{4 x + 9} = 1 i s :$

Q. Solve the following equation and find the value of

x

2^{x + 3} = 4^{x - 1}

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what is d value of 'x' in d following equation : [(4x + 3) / 4 ] - { x - [(2x-1) / 3] } = x + (1 / 3)

what is d value of 'x' in d following equation :
[(4x + 3) / 4 ] - { x - [(2x-1) / 3] } = x + (1 / 3)