what is oxidation number of iodine in KI3 and carbons in CH3CH2OH

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Solution

KI₃ is actually formed between K+ and I₃^- ions. In I₃^-ion there is a 3 centre 4 electron bond between I₂ & I^- ions, thus making the oxidation state of iodine as -1 as the oxidation states of I atoms in I₂ is taken as zero.

²CH₃¹CH₂OH = Ox. No. of C₁ = +1 (due to O) + [-2] due to 2H atoms + 0 (one C atom) = -1

Similarly, C₂ = -3 due to 3 H atoms and 0 for 1 C atom = -3

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