what is the current drawn when a kettle of power 1.65 k W is connected to an 110v power supply?

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Solution

Given, P = 1.65 kW = 1650 Watts
V = 110 volts
As P = V I
Therefore, I = P/V = 1650/ 110 = 15 A

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what is the current drawn when a kettle of power 1.65 k W is connected to an 110v power supply?

Given, P = 1.65 kW = 1650 Watts V = 110 volts As P = V I Therefore, I = P/V = 1650/ 110 = 15 A

Given, P = 1.65 kW = 1650 Watts
V = 110 volts
As P = V I
Therefore, I = P/V = 1650/ 110 = 15 A