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Question

what is the derivative of e^sinex^1/2 by chain rule.

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Solution

ddxesinxxUsing product rule,=xddxesinx+esinxddxxUsing chain rule we haveddxesinx=deudud sinxdx=eucosx=esinxcosxSo we have=xesinxcosx+esinx12x=esinx(xcosx+12x) Ans

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