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Breaking a Capacitor into Combinations

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Question

What is the effect on capacitance of a parallel plate capacitor when a dielectric slab is introduced between the plates?

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Solution

$C a p a c i \tan c e o f t h e p a r a l l e l p l a t e c a p a c i t o r i s g i v e n b y : C_{0} = \frac{ε_{o} A}{d} w h e r e A i s t h e a r e a o f t h e p l a t e d i s t h e d i s \tan c e b e t w e e n t h e p l a t e s w h e n d i e l e c t r o c s l a b o f d i e l e c t r i c c o n s \tan t k (k > 1) i s i n t r o d u c e d i n b e t w e e n t h e p l a t e . C a p a c i \tan c e i s g i v e n b y : C = \frac{k ε_{o} A}{d} C = k C_{0} s o c a p a c i \tan c e i n c r e a s e d b y t h e k t i m e t o t h e i n i t i a l v a l u e .$

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