what is the mass of 56 cm3 of carbon monoxide at stp?

Open in App

Solution

At STP, 1 mole of any gas has a volume of 22.4 L.
Molar mass of CO = 12 + 16 = 28 g/mol
Therefore,
22.4 L ( 22400 cm³) is the volume of 28g CO at STP
56 cm³ will be the volume of (28/22400) x 56 = 0.07 g of COat STP.

Suggest Corrections

Similar questions

What is the mass of $56 c m^{3}$ of carbon monoxide at STP?
$[C = 12; O = 16] |$

Waht is the mass of $56 c m^{3}$ fo carbon monoxide at STP?
\([C = 12; O = 16]|)

(a) Calculate the number of moles in 7 g of nitrogen.
(b) What is the volume at STP of 7.1 g of chlorine?
(c) What is the mass of 56 $c m^{3}$ of carbon monoxide at STP?

Q. What is the volume of

14 g

of carbon monoxide at STP?

1litre of O₂ at STP is made to react with 3litre of carbon monoxide at STP . Calculate the mass of each substance formed after the reaction?

Join BYJU'S Learning Program

what is the mass of 56 cm3 of carbon monoxide at stp?

At STP, 1 mole of any gas has a volume of 22.4 L. Molar mass of CO = 12 + 16 = 28 g/mol Therefore, 22.4 L ( 22400 cm3) is the volume of 28g CO at STP 56 cm3 will be the volume of (28/22400) x 56 = 0.07 g of CO at STP.

At STP, 1 mole of any gas has a volume of 22.4 L.
Molar mass of CO = 12 + 16 = 28 g/mol
Therefore,
22.4 L ( 22400 cm³) is the volume of 28g CO at STP
56 cm³ will be the volume of (28/22400) x 56 = 0.07 g of COat STP.