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Question

what is the molarity of acetic acid containing 6gm of acetic acid per litre of solution.

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Solution

molarity = moles of solute/ litres of solution
Molar mass of acetic acid (CH₃COOH) = 12 + 3 x 1 + 12 + 2 x 16 + 1
= 60 g/mol
Number of moles in 6 gm acetic acid = 6/60 = 0.1
Molarity = 0.1/1 = 0.1 M

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