What is the oxidation number of hydrogen, oxygen sulphur in the equation H2SO4? How to make out which element posses which oxidation number? Is oxidation number equals its valency? Then why not oxidation number of sulphur -2?

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Solution

Hydrogen carry the oxidation state of +1 in all its compound except hydrides. Oxygen carries -2 charge in all its compound except peroxide and super oxide.
In case of H₂SO₄ = Oxidation state of sulphur is given by putting the value of +1 for Hydrogen and -2 for Oxygen. = +6
Oxidation state of S is +6.
Oxidation no. may equals to valency with formal charge in most of the cases but not always

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