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Question

What is the probability of-

i) Sundays in a leap year

ii) sundays in a non-leap year

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Solution

(i) A leap year has 366 days, therefore 52 weeks i.e. 52 Sunday and 2 days. The remaining 2 days may be any of the following :(i Sunday and Monday(ii) Monday and Tuesday(iii) Tuesday and Wednesday(iv) Wednesday and Thursday(v) Thursday and Friday(vi) Friday and Saturday(vii) Saturady and SundayFor having 53 sundays in a year, one of the remaining 2 days must be a Sunday.n(S)= 7n(E) = 2P(E)=n(E)/n(S)= 2/7

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