Question

what is the upthrust experienced by a cube of edge length = 5 cm made of iron when completely immersed in ethanol ofdensity 0.8 g/cm3?

Answer 1

Buoyant force = dVg
d = density of the liquid
V = volume of the liquid displaced
g = acceleration due to gravity
For given cube,
$$\begin{gathered} \mathrm{V}=\mathrm{Volume}\mathrm{of}\mathrm{cube}={\mathrm{Length}}^3=5^3=125{\mathrm{cm}}^3 \\ \mathrm{d}=0.8\mathrm{g}/{\mathrm{cm}}^3 \\ \mathrm{g}=981\mathrm{cm}/{\mathrm{s}}^2 \\ \mathrm{Thus}, \\ \mathrm{F}=125\times 0.8\times 981=98100\mathrm{g}.\mathrm{cm}/{\mathrm{s}}^2 \end{gathered}$$