What will be the resistance of a conductor if its length is increased by 3 times and area of cross section becomes half . also find the specific resistance of the conductor.
we know that resistance is given as
R = ÏL/A
so,
R ~ L
and
R ~ 1/A
so
R ~ L/A
the new resistance will be
R' ~ L'/A'
here,
L' = 3L
and
A' = A/2
so,
R' ~ 3L/(A/2)
~ 6(L/A)
thus,
R' ~ 6R
the resistance will increase six times its initial value.