Whatsis the reciprocal of (1/3)^_-3?

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Solution

$L e t x = (\frac{1}{3})^{- 3} N o w a s w e k n o w (a)^{- b} = (\frac{1}{a})^{b} H e n c e x = (3)^{3} = 27 N o w a s w e k n o w r e c i p r o c a l o f m i s \frac{1}{m} H e n c e r e c i p r o c a l o f 27 i s \frac{1}{27}$

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Similar questions

What is the reciprocal of $\frac{1}{3}$ ?

The reciprocal of $\frac{1}{3}$ is 3.

\frac{1}{3}

\frac{2}{5} \times \frac{- 10}{3}

(\frac{1}{2} - \frac{1}{3})

(\frac{1}{3}) + {(\frac{4}{5})}^{- 3}

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