When velocity is halved,its kinetic enegy becomes 1/4 or not?

Open in App

Solution

Since, K.E. = 1/2 mv²
when v' = v/2
then, K.E.^' = 1/2 m v'² = $\frac{1}{2} m {(\frac{v}{2})}^{2} = \frac{1}{2} X \frac{m v^{2}}{4} = \frac{K . E .}{4}$

Suggest Corrections

Similar questions

Q. State whether the given statement is True or False :

When velocity is halved, its kinetic energy becomes 1/4th.

If the velocity of a moving car is halved, its kinetic energy would

A body of mass 5 kg is moving with a velocity of 10 m s^-1. The ratio of its initial kinetic energy and final kinetic energy, if the mass of the body is doubled and its velocity is halved will be

Q. When the mass of body is halved and velocity is doubled, then the kinetic energy of the body

A body of mass 10 kg is moving with a velocity 20 m $s^{- 1}$ . If the mass of the body is doubled and its velocity is halved, find:(i) the initial kinetic energy, and (ii) the final kinetic energy.

Join BYJU'S Learning Program

When velocity is halved,its kinetic enegy becomes 1/4 or not?

Since, K.E. = 1/2 mv2 when v' = v/2 then, K.E.' = 1/2 m v'2 = 12 m v22 = 12 X m v24 = K.E.4

Since, K.E. = 1/2 mv²
when v' = v/2
then, K.E.^' = 1/2 m v'² = $\frac{1}{2} m {(\frac{v}{2})}^{2} = \frac{1}{2} X \frac{m v^{2}}{4} = \frac{K . E .}{4}$