Which of the following configurations would you expect to have the lowest ionization energy.
a) 1s2 2s2 2p6.
b) 1s2 2s2 2p5.
c) 1s2 2s2 2p6 3s1.
Here, the lowest ionization energy will be for the third configuration i.e. 1s22s22p6 3s1 ,as the outermost orbital (3s) has only one electron which can be easily removed in low energy requirements and so its I.E is least.