In NH3, H2O and H2S, Nitrogen , oxygen and sulphur respectively undergo sp3 hybridisation forming four hybrid orbitals. The expected bond angle is 109o28'.
In case of O and S, oxygen is smaller in size than sulphur and is highly electronegative, the bond pairs are closer to O atom and hence the repulsion between them are large. As we move dowm to S, electronegativity decreases due to which the bond pairs move away from the central atom. Hence the repulsions between the bond pairs decrease, so the bond angle also decreases.
Same is the case with NH3 and H2S. Bond angle of NH3 is larger than H​2S, because N is smaller than S and also it is more electronegative than S.