why more charge on a body means more force of attraction or repulsion?

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Solution

$E l e c t r o s t a t i c f o r c e o f a t t r a c t i o n o r r e p u l s i o n i s g i v e n b y : F = \frac{k q_{1} q_{2}}{r^{2}} w h e r e q_{1} a n d q_{2} a r e t h e c h a r g e s o n t w o b o d i e s . A s f o r c e i s d i r e c t l y p r o p o r t i o n a l t o t h e c h a r g e o n b o d y t h e r e f o r e w h e n c h a g e o n t h e b o d y i n c r e a s e s, f o r c e o f a t t r a c t i o n o r r e p u l s i o n i n c r e a s e s .$

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