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Moseley's Law

WHY THE METAL...

Question

WHY THE METALLIC RADII OF THE 3RD (5D) SERIES OF TRANSITION ELEMENTS ARE VIRTUALLY THE SAME AS THOSE OF THE CORRESPONDING MEMBERS OF THE SECOND SERIES?

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Solution

Its because of lanthanoid contraction. the imperfect shielding effect by the f-orbital causes this effect. The filling of 4f orbital before 5d results in regular decrease in size of atoms.

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Similar questions

Q. Assertion :In transition elements, radii of

5 d

series are virtually the same as those of the corresponding members of

4 d

series. Reason: The filling of

4 f

orbitals before

5 d

orbitals results in a regular decrease in atomic radii.

Q. How would you account for the following:
(i) Many of the transition elements are known to form interstitial compounds.
(ii) The metallic radii of the third (5d) series of transition metals are virtually the same as those of the corresponding group members of the seconds (4d) series.
(iii) Lanthanoids form primarily +3 ions, while the actinoids usually have higher oxidation states in their compounds, +4 or even +6 being typical.

Q. How would you account for the following:
(i) Among lanthanoids, Ln (III) compounds are predominant. However, occasionally in solution or in
solid compounds, +2 and +4 ions are also obtained.
(ii) The

E_{M^{2 +} / M}^{o}

for copper is positive (0.34 V). Copper is the only metal in the first series of transition elements showing this behavior.
(iii) The metallic radii of the third (5d) series of transition metal are nearly the same as those of the corresponding members of the second series.

Q. Why the atomic radii of the second and third transition series are almost same?

5 d

transition series elements have higher ionization enthalpies than

4 d

transition series elements ?

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