write the equatio to show the actionof ozone on potassium iodide
Reaction of ozone with potassium iodide:
O3 + 2KI + H2O -------> O2 + I2 + 2KOH
Above reaction occurs in a neutral solution, which then becomes alkaline. In presence of alkali, the iodine is partly converted into iodide and iodate, but is wholly liberated again on acidifying:
3I2 + 6KOH = 5KI + KIO3 + 3H2O;
5KI + KIO3 + 3H2SO4 = 3K2SO4 + 3I2 + 3H2O.
Moist iodine is oxidised to iodic acid, HIO3:
I2 + 5O3 + H2O = 2HIO3 + 5O2