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Byju's Answer
Standard XII
Mathematics
Multinomial Theorem
Px1, y1 and ...
Question
P
(
x
1
,
y
1
)
and
Q
(
x
2
,
y
2
)
are points in the plane such that
P
Q
subtends a right angle at the origin
O
, then
A
P
(
1
,
3
)
,
Q
(
−
3
,
1
)
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B
P
(
3
,
1
)
,
Q
(
1
,
−
3
)
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C
P
(
2
,
5
)
,
Q
(
5
,
−
2
)
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D
P
(
1
,
1
)
,
Q
(
−
1
,
1
)
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Solution
The correct options are
A
P
(
3
,
1
)
,
Q
(
1
,
−
3
)
B
P
(
2
,
5
)
,
Q
(
5
,
−
2
)
C
P
(
1
,
1
)
,
Q
(
−
1
,
1
)
D
P
(
1
,
3
)
,
Q
(
−
3
,
1
)
As
P
Q
subtends a right angle at the origin
O
,
then.
⇒
(
O
P
)
2
+
(
O
Q
)
2
=
(
P
Q
)
2
⇒
(
x
2
1
+
y
2
1
)
+
(
x
2
2
+
y
2
2
)
=
(
x
1
−
x
2
)
2
+
(
y
1
−
y
2
)
2
⇒
(
x
1
x
2
+
y
1
y
2
)
=
0
Then from aptions
(
A
)
1.
(
−
3
)
+
(
3
)
.
(
1
)
=
−
3
+
3
=
0
(
B
)
3.1
+
1.
(
−
3
)
=
3
−
3
=
0
(
C
)
2.5
+
(
5
)
.
(
−
2
)
=
10
−
10
=
0
(
D
)
1.
(
−
1
)
+
(
1
)
.
(
1
)
=
1
+
1
=
0
Hence All the options are true.
Suggest Corrections
0
Similar questions
Q.
If the line segment joining the points P (x
1
, y
1
) and Q (x
2
, y
2
) subtends an angle α at the origin O, prove that
OP · OQ cos α = x
1
x
2
+ y
1
, y
2