$p (x) = 63 - 9 x$ is a _______ polynomial.

constant

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linear

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quadratic

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cubic

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Solution

The correct option is C linear
The general form of linear polynomial is $p (x) = a x + b$ where $x$ is a variable and $b$ is a constant. The first term of this polynomial has power $1$ and therefore, the degree of the polynomial is $1$ .

Similarly, the polynomial $p (x) = 63 - 9 x$ or $p (x) = - 9 x + 63$ has degree $1$ .

Hence, the polynomial $p (x) = 63 - 9 x$ is a linear polynomial.

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Similar questions

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If $p (x) = x^{3} - 3 x^{2} - 9 x - 9$ , find p(0), p(3), p(-3) and p(-1). What do you condlude about the zeros of p(x)? Is 0 a zero p(x)?

9 x

\equiv

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Using the remainder theorem, find the remainder, when p(x) is divided by g(x), where $(p x) = x^{3} - 6 x^{2} + 9 x + 3, g (x) = x - 1$

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