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Question

p(x)=x23x+2,q(x)=3x+1
(a) Find p(x)+q(x)
(b) If p(x)+q(x)+r(x)=0, find r(x).
(c) What number is p(1)+q(1)+r(1)?

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Solution

(a) P(x)+q(x)=x23x+2+3x1=x2+1
(b) P(x)+q(x)+r(x)=0x2+1+r(x)=0
r(x)=x21
(c) P(1)+q(1)+t(1)=0.(bczP(x)+q(x)+r(x)=0)

1126277_1295784_ans_58f5ac97f5454e6a92a84f923f1cac7f.JPG

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