Question

$p\left(x\right)=x^2-7\sqrt{7}x+3$, then $p\left(7\sqrt{7}\right)=$

• A. $3$
• B. $7\sqrt{7}$
• C. $42\sqrt{7}+3$
• D. $49\sqrt{7}$

Answer 1

The correct option is A $3$

Given,

$p\left(x\right)=x^2-7\sqrt{7}x+3$

$⟹p\left(7\sqrt{7}\right)=(7\sqrt{7}{)}^2-7\sqrt{7}\times 7\sqrt{7}+3$

$=343-343+3=3$

Hence $p\left(7\sqrt{7}\right)=3$