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Question

P4+5O2P4O10 If 31 g of P4 is reacted with excess of oxygen, the % yield is 60%, then the amount of product formed is.

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Solution

1. The given reaction is:

P4+5O2P4O10

2. Here, one mole of phosphorous is reacting with 5 moles of oxygen to give one mole ofP4O10

3. The mass of P4=4×31=124gm

4. The mass of P4O10=4×31+10×16=284gm

5. If the yield is 100%, then 31 gm of P4 will give =31×284124=71gmofP4O10

6. The percentage of yield is 60%, then the amount of product P4O10 formed is:

Theamountofproduct=71×60%

=71×60100

=42.6gofP4O10


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