PA and PB are tangents to the circle with centre O drawn from external point P, QR ia a tangent at point S, then PQ+QS=PR+RS. that relation is ?

True

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False

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Solution

The correct option is A True
Given: $P A$ and $P B$ are tangents
Tangents drawn from an external point are equal.
$\Rightarrow A P = B P, A Q = Q S, B R = R S$
Now, $A P = B P$
$\Rightarrow P Q = A Q = P R = B R$
$∴ P Q + Q S = P R + R S ∵ A Q = Q S a n d B R = R S$
Hence the relations $P Q + Q S = P R + R S$ is true.

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PA and PB are tangents to the circle with centre O drawn from external point P, QR ia a tangent at point S, then PQ+QS=PR+RS. that relation is ?

The correct option is A TrueGiven:PA and PB are tangentsTangents drawn from an external point are equal.⇒AP=BP,AQ=QS,BR=RSNow,AP=BP⇒PQ=AQ=PR=BR∴PQ+QS=PR+RS∵AQ=QSandBR=RSHence the relations PQ+QS=PR+RS is true.