___ $P a$ is the pressure at a depth of $10 m$ below the surface of the kerosene. The density of kerosene is $800 k g / m^{3}$ . Take $g$ = $10 m / s^{2}$

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Solution

The expression for the pressure at the bottom of a liquid at height ‘h’ with density ‘d’ is given by $d g h .$
The given values are: $d = 800 k g / m^{3}$ , $h = 10 m$ and $g$ = $10 m / s^{2}$
Thus, $p r e s s u r e = d g h$
$= 800$ $\times$ $10 \times 10 = 80000 P a$ .

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