___Pa is the pressure at a depth of 10m below the surface of the kerosene. The density of kerosene is 800kgm3.
Open in App
Solution
The expression of pressure at the bottom of a liquid of height ‘h’ and density ‘d’ is given by ρgh. The given values are: d=800kgm3, h=10mandg=10ms2. Thus, pressure=ρgh =800×10×10=80000Pa .