Question

Paheli prepared a blue coloured solution of copper sulphate in beaker A and placed an iron nail in it. Boojho prepared a yellowish green solution of ferrous sulphate in beaker B and placed a copper wire in it. What changes will they observe in the two beakers after an hour?

Answer 1

Iron is more reactive than Copper and thus it displaces Copper from its salt solution. In beaker A, Copper's reddish brown layer will deposit on the iron nail and copper sulphate's blue colour solution will become yellowish green because this process forms Iron sulphate. In beker B, There's no change because the less reactive property of copper doesn't be able to displace iron from ferrous sulphate solution.