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Question
Paheli prepared a blue-coloured solution of copper sulphate in beaker A and placed an iron nail in it. Boojo prepared a yellowish-green solution of ferrous sulphate in beaker B and placed a copper wire in it. What changes will they observe in the two beakers after an hour?
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Solution
The metal which is more reactive displaces the metal that is less reactive from its salt solution.
In the reactivity order of metals:
Iron is more reactive than copper.
Beaker A:
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As iron is more reactive than copper it displaces copper from blue coloured copper sulphate solution.
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Forms a yellowish-green iron sulphate solution.
Beaker B:
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Copper being less reactive than iron cannot displace iron from yellowish-green iron sulphate solution.
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No change happens.
In the reactivity order of metals:
Iron is more reactive than copper.
Beaker A:
-
As iron is more reactive than copper it displaces copper from blue coloured copper sulphate solution.
-
Forms a yellowish-green iron sulphate solution.
Beaker B:
-
Copper being less reactive than iron cannot displace iron from yellowish-green iron sulphate solution.
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No change happens.
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