Pairs of electrodes and their corresponding standard electrode potentials are given- Arrange the cells constructed by these electrodes in increasing order of emf values- a Electrode - A-Eo-2-92V and Electrode - B- Eo-2-71V b Electrode - C-Eo-0-760V and Electrode - D- Eo-0-44V cElectrode - B-Eo-2-71V and Electrode - D- Eo-0-44V d Electrode - A-Eo-2-92V and Electrode - C- Eo-0-76V

The correct option is B abdc The potential difference is called the nbsp;cell potential (or EMF for electromotive force) which is represented as E_( ...

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Standard XII

Chemistry

SHE

Pairs of elec...

Question

Pairs of electrodes and their corresponding standard electrode potentials are given. Arrange the cells constructed by these electrodes in increasing order of emf values.

$(a) E l e c t r o d e \to A, E^{o} = - 2.92 V$ and $E l e c t r o d e \to B, E^{o} = - 2.71 V$
$(b) E l e c t r o d e \to C, E^{o} = - 0.760 V$ and $E l e c t r o d e \to D, E^{o} = - 0.44 V$
$(c) E l e c t r o d e \to B, E^{o} = - 2.71 V$ and $E l e c t r o d e \to D, E^{o} = - 0.44 V$
$(d) E l e c t r o d e \to A, E^{o} = - 2.92 V$ and $E l e c t r o d e \to C, E^{o} = - 0.76 V$

b a d c

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a b d c

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b d a c

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b d c a

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Solution

The correct option is B $a b d c$
The potential difference is called the cell potential (or EMF for electromotive force) which is represented as $E_{(C e l l)} = E_{(c a t h o d e)} - E_{(a n o d e)}$ . The EMF values for above cells are $(a) = - 0.21 V, (b) = - 0.32 V, (c) = - 2.27 V a n d (d) = - 2.16 V$ . Increasing order of emf values = $a b d c$

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Similar questions

Q. The standard electrode potentials of the electrodes are given below. Arrange them in decreasing order of ease of oxidation:

(a) E l e c t r o d e - I, E^{o} = - 2.89 V

(b) E l e c t r o d e - I I, E^{o} = - 0.16 V

(c) E l e c t r o d e - I I I, E^{o} = 0.77 V

(d) E l e c t r o d e - I V, E^{o} = - 2.93 V

(e) E l e c t r o d e - V, E^{o} = - 1.67 V

Q. From the standard electrode potential values of the electrodes given select an option representing their decreasing order discharge potential:

(a) A, E^{o} = 2.32 V

(b) B, E^{o} = 1.36 V

(c) C, E^{o} = 1.07 V

(c) D, E^{o} = 0.43 V

Q. Given standard electrode potentials :

{F e}^{3 +} + {3 e}^{-} ⟶ F e; E^{o} = - 0.036 v o l t

{F e}^{2 +} + {2 e}^{-} ⟶ F e; E^{o} = - 0.440 v o l t

The standard electrode potential

E^{o}

for

{F e}^{3 +} + e^{-} ⟶ {F e}^{2 +}

is:-

Q. Given, standard electrode potentials,

F e^{2 +} + 2 e^{-} \to F e, E^{o} = - 0.440

F e^{3 +} + 3 e^{-} \to F e, E^{o} = - 0.036

The standard electrode potential

(E^{o})

for

F e^{3 +} + e^{-} \to F e^{2 +}

is:

Q. Given standerd electrode potentials

F e^{2 +} + 2 e^{-}

⟶

F e; E^{o} = - 0.440 V

F e^{3 +} + 3 e^{-}

⟶

F e; E^{o} = - 0.036 V

The standard electrode potential

(E^{o}

) for

F e^{3 +} + e^{-}

\to

F e^{2 +}

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The correct option is B abdcThe potential difference is called the cell potential (or EMF for electromotive force) which is represented as E(Cell)=E(cathode)−E(anode). The EMF values for above cells are (a)=−0.21V,(b)=−0.32V,(c)=−2.27Vand(d)=−2.16V. Increasing order of emf values = abdc