wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Paragraph for below question
नीचे दिए गए प्रश्न के लिए अनुच्छेद

Roots of x2 + 6x + 12 = 0 are α and β, where α and β are complex numbers, then

समीकरण x2 + 6x + 12 = 0 के मूल α व β हैं, जहाँ α व β सम्मिश्र संख्याएं हैं, तब

Q. |α2 – β2| is

प्रश्न - |α2 – β2| का मान है

A
83
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
63
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
123
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
123
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 123
Solution

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Conjugate of a Complex Number
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon